A coincidence problem in telephone traffic with non-recurrent arrival process

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On A Telephone Problem

Answer. Let f(n) be the minimum number of calls needed for n people. It is easily shown that f(1) = 0, f(2) = 1, f(3) = 3 and f(4) = 4. For n > 4, 2n− 4 calls are sufficient according to the following procedure: one of four “chief” gossips first calls each of the remaining n− 4 gossips, then the four learn each other’s (and hence everyone’s) information in 4 calls (as f(4) = 4), and finally one...

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ژورنال

عنوان ژورنال: Journal of the Australian Mathematical Society

سال: 1963

ISSN: 0004-9735

DOI: 10.1017/s144678870002797x